The probability of a man hitting a target is 110. The least number of shots required, so that the probability of his hitting the target at least once is greater than 14, is
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answer is 3.
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Detailed Solution
Given success probability is p=110;q=1-p=910px≥1=1−px=1=1−910n≥14it implies 0.9n≤34The possible value of n is =3