First slide

Theorems of probability

Question

The probability that a non leap year will have 53 wednesdays is

Very Easy

A

$\frac{1}{7}$
B

$\frac{2}{7}$
C

$\frac{5}{7}$
D

$\frac{6}{7}$

Solution

$365 d a y s = 52 w + 1 d a y$
$n (S) = 7; n (A) = 1$

$p (A) = \frac{1}{7}$

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