Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

The probability that when 12 distinct balls are distributed among three boxes, the first will contain exactly three balls is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

29312

b

12C3⋅2996

c

12C3⋅212312

d

12C3⋅39312

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

3 balls for 1st Box can be selected in  12C3 ways, remaining 9 balls can be placed in remaining 2 boxes in 29 ways.Number of favourable cases =12C3×29Total number of cases = 312Required Probability = 12C3×29312= 12C3×2996
Watch 3-min video & get full concept clarity

courses

No courses found

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon