Q.

The probability that when 12 distinct balls are distributed among three boxes, the first will contain exactly three balls is

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a

29312

b

12C3⋅2996

c

12C3⋅212312

d

12C3⋅39312

answer is B.

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Detailed Solution

3 balls for 1st Box can be selected in  12C3 ways, remaining 9 balls can be placed in remaining 2 boxes in 29 ways.Number of favourable cases =12C3×29Total number of cases = 312Required Probability = 12C3×29312= 12C3×2996
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