Questions
A problem in mathematics is given to three students A, B, C and their respective probability of solving the problem is 1/2, 1/3, and 1/4. Probability that the problem is solved is
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Correct option is A
P(A)=12,P(B)=13, and P(C)=14∴ P(A¯)=1−12=12,P(B¯)=1−13=23 P(C¯)=1−14=34Therefore, the required probability is1−P(A¯)P(B¯)P(C¯)=1−12×23×34=1−14=34Similar Questions
The odd against an event are 5 to 2 and the odds in favour of another disjoint event are 3 to 5. Then the probability that atleast one of the events will happen is
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