A problem in mathematics is given to three students A, B, C and their respective probability of solving the problem is 1/2, 1/3, and 1/4. Probability that the problem is solved is

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3/4

1/2

2/3

1/3

answer is A.

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Detailed Solution

P(A)=12,P(B)=13, and P(C)=14∴ P(A¯)=1−12=12,P(B¯)=1−13=23 P(C¯)=1−14=34Therefore, the required probability is1−P(A¯)P(B¯)P(C¯)=1−12×23×34=1−14=34

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