The product of all real roots of the equation x2-x-6=0 is

Given equation x2-x-6=0If x>0, ∴ equation is x2-x-6=0⇒(x-3)(x+2)=0⇒x=3, x=-2⇒x=3If x<0, ∴ equation is x2+x-6=0⇒(x+3)(x-2)=0⇒x=-3, x=2⇒x=-3Hence product of all possible real roots =-9.