Questions
The product of the perpendicular from origin to the pair of lines is
a
−7145
b
7145
c
1457
d
-1457
detailed solution
Correct option is B
The product of the perpendiculars drawn from the point P0,0to the pair of lines represented by the equation ax2+2hxy+by2+2gx+2fy+c=0 is ca−b2+4h2For the equation 5x2+12xy+6y2+x+y−7=0the product of the perpendiculars from the point 0,0 is dd=−75−62+122 =7145Therefore, the required distance is 7145Talk to our academic expert!
Similar Questions
The product of the perpendicular from (1,1) to the pair of lines is 1 then
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