The product of the perpendicular from 1,1 to the pair of lines x2+2xy+y2+2x+2y+1=0 is
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a
−29
b
29
c
92
d
−92
answer is C.
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Detailed Solution
The product of the perpendiculars drawn from the point Px1,y1to the pair of lines represented by the equation ax2+2hxy+by2+2gx+2fy+c=0 is ax12+2hx1y1+by12+2gx1+2fy1+ca−b2+4h2For the equation x2+2xy+y2+2x+2y+1=0the product of the perpendiculars from the point (1,1) is dd=12+211+12+21+21+11−12+22=94=92Therefore, the product of the perpendiculars drawn from the point (1,1) to the pair of linesx2+2xy+y2+2x+2y+1=0 is 92 units