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Questions  

The product of the perpendicular from (1,1) to the pair of lines x2+2xy+y2+kx+2y+5=0 is 2 then k=k<0
 

a
22−11
b
22+11
c
11−22
d
−11−22

detailed solution

Correct option is C

The product of the perpendiculars drawn from the point Px1,y1to the pair of lines represented by the equation ax2+2hxy+by2+2gx+2fy+c=0 is ax12+2hx1y1+by12+2gx1+2fy1+ca−b2+4h2For the equation x2+2xy+y2+kx+2y+5=0 the product of the perpendiculars from the point (1,1) is 2.2=12+211+12+k1+21+51−12+22=11+k4=11+k2Squaring on both sides and then simplify, take only positive value for k 11+k=22k=22−11Therefore, the value of k is 22−11

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The product of the perpendicular from (1,1) to the pair of lines ax22hxy+by2=0 is 1 then 1a+1b


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