The product of roots of the equation log8⁡8/x2log8⁡x2=3 is

Let log8⁡x=y,   then the given equation reduces to (1−2y)/y2=3⇒ 3y2+2y−1=0(3y−1)(y+1)=0⇒log8⁡x=y=1/3,−1⇒ x=2,1/8