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The product of three consecutive natural numbers is divisible by
Let be there consecutive natural number and let be their product. Then,
We have
which is divisible by 3 and 6
which is divisible by 3, 8 and 6
which is divisible by 3 and 6.
which is divisible by 3, 8 and 6.
Hence, is divisible by 6 for all
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For all is divisible by
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