The projection of the line x+1−1=y2=z−13 in the plane x-2y+z=6 is the line of intersection of this plane with the plane is

Equation of a plane through (-1,0,1) is a(x+1)+b(y−0)+c(z−1)=0Which is parallel to the given line and perpendicular to the given plane.−a+2b+3c=0 and a−2b+c=0 by solving the above, we get , c=0, a=2b