Download the app

Questions  

 The projection of the line x+11=y2=z13 on the plane x2y+z=6 is the line of intersection of this plane with the plane

a
2x+y+2=0
b
3x+y−z=2
c
2x−3y+8z=3
d
none of these

detailed solution

Correct option is A

Equation of the plane through (-1, 0, 1) is a(x+1)+b(y−0)+c(z−1)=0-------iwhich is parallel to the given line and perpendicular to the given plane −a+2b+3c=0----iiand    a−2b+c=0----iiiFrom Eqs. (ii) and (iii), we get c=0,a=2b From Eq. (i) 2b(x+1)+by=0⇒2x+y+2=0

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

The equation of a plane which passes through the point of intersection of lines x13=y21=z32 and x31=y12=z23 and at greatest distance from point (0,0,0) is


phone icon
whats app icon