First slide

Introduction to mathematical reasoning

Question

The proposition $(p \to\sim p) \land (~ p \to p)$ is a

Moderate

A

tautology and contradiction
B

neither tautology nor contradiction
C

contradiction
D

tautology

Solution

$p$ $~ p$ $p \to\sim p$ $~ p \to p$ $(p \to\sim p) \land (~ p \to p)$
T F F T F
F T T F F
Clearly, $(p \to\sim p) \land (~ p \to p)$ is a contradiction.

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App