The proposition p→∼(p$$∧~$$q) is

Correct option is 4neither (1) nor (2)

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The proposition $p \to\sim (p \land ~ q)$ is

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a contradiction

a tautology

either (1) or (2)

neither (1) nor (2)

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Correct option is D

Result is neither tautology nor contradiction.

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The proposition p→∼(p∧~q) is

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The proposition $p \to\sim (p \land ~ q)$ is