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The proposition $~ (p \Rightarrow q) \Rightarrow (~ p \lor ~ q)$ is

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a Tautology

a Contradiction

either (a) or (b)

neither (a) nor (b)

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detailed solution

Correct option is A

By truth tableHence, given proposition is a tautology.

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The proposition ~(p⇒q)⇒(~p∨~q) is

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The proposition $~ (p \Rightarrow q) \Rightarrow (~ p \lor ~ q)$ is