1q+r, 1r+p,1p+q are in A.P., then:
p, q, r are in A.P.
p2, q2, r2 are in A.P.
1/p, 1/q, 1/r are in A.P.
None of these
1/(q+r), 1/(r+p), 1/(p+q) are in A.P.
⇒ 1r+p−1q+r=1p+q−1r+p
⇒q-pr+pr+q=r-qp+qr+p
⇒ q2−p2=r2−q2 ⇒p2, q2, r2 are in A.P.