A quadratic equation whose roots are (γα)2 and (βα)2 , where α,β,γ are roots of x3+27=0 is
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a
x2−x+1=0
b
x2+3x+9=0
c
x2+x+1=0
d
x2−3x+9=0
answer is C.
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Detailed Solution
Given that, x3+27=0 ⇒x3=(−3)3 ⇒x=−3,−3ω,−3ω2 ∴ γα=−3ω2−3⇒γα=ω2, And βα=−3ω−3⇒βα=ω ∴ (γα)2=ω4=ω and (βα)2=ω2 sum of the roots : (γα)2 +(βα)2 =ω+ω2 product of the roots : (γα)2 (βα)2 =ω3 ∴ The required equation is x2−((γα)2+(βα)2)x+(γα)2(βα)2=0 ⇒x2−(ω+ω2)x+ω3=0 ⇒x2+x+1=0 .