Download the app

Questions  

A quadratic equation whose roots are cosec2θ and sec2θ can be

a
x2−2x+2=0
b
x2−3x+3=0
c
x2−x+1=0
d
None of these

detailed solution

Correct option is D

Sum of roots=sec2θ+cosec2θ=1cos2θ+1sin2θ                                                                                             = 4sin22θ≥4Also, product of roots=sec2θcosec2θ=4sin22θ≥4∴The required quadratic equation will be x2−tx+t=0 where t≥4.

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

If secx+sec2x=1 then the value of tan8xtan4x2tan2x+1 is equal to


phone icon
whats app icon