For the quadratic equation x2+2(a+1)x+9a−5=0, which of the following is/are true?

Given equation is x2+2(a+1)x+9a−5=0D=4(a+1)2−4(9a−5)=4(a−1)(a−6)∴ D≥0⇒a≤1 or a≥6⇒ roots are real lf a < 0, then 9a - 5 < 0. Hence, the products of roots is less than 0. So, the roots are of opposite sign .lf a > 7 , then sum of roots is -2(a + 1) < 0. Product of roots is greater than 0.