Questions
A quadratic function y=f(x) if it touches the line y=x at the point x=1 and passes through the point (-1, 0)
a
(x+1)2
b
12(x+1)2
c
14(x+1)2
d
x(x+1)
detailed solution
Correct option is C
y=f(x)=ax2+bx+cf′(x)=2ax+b=1 at x=1⇒2a+b=1----1x=1_,_y=1⇒f(1)=1⇒a+b+c=1----2 Solving (1)&2 curve passes through (−1,0)a=14b=12c=14Fx==x24+x2+14=x2+2x+14=14(x+1)2Talk to our academic expert!
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