First slide
Equation of line in Straight lines
Question

qx+py+(p+qr)=0 is the reflection of the line   px+qy+r=0 in the line 

Moderate
Solution

Equation of the bisectors of the angle between the given lines are

px+qy+rp2+q2=±qx+py+(p+qr)p2+q2

Taking the negative sign we get x+y+1=0 

so one is the reflection of the other line, in the line x+y+1=0.

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