qx+py+(p+q−r)=0 is the reflection of the line px+qy+r=0 in the line
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a
x–y=p+q
b
x–y=p-q
c
x+y+1=0
d
x+y–1=0
answer is C.
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Detailed Solution
Equation of the bisectors of the angle between the given lines arepx+qy+rp2+q2=±qx+py+(p+q−r)p2+q2Taking the negative sign we get x+y+1=0 so one is the reflection of the other line, in the line x+y+1=0.