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$qx + py + (p + q - r) = 0$ is the reflection of the line $px + qy + r =0$ in the line

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x–y=p+q

x–y=p-q

x+y+1=0

x+y–1=0

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detailed solution

Correct option is C

Equation of the bisectors of the angle between the given lines arepx+qy+rp2+q2=±qx+py+(p+q−r)p2+q2Taking the negative sign we get x+y+1=0 so one is the reflection of the other line, in the line x+y+1=0.

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qx+py+(p+q−r)=0 is the reflection of the line px+qy+r=0 in the line

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$qx + py + (p + q - r) = 0$ is the reflection of the line $px + qy + r =0$ in the line