R(–1, 4),S(11,–8)divide AB harmonically in the ratio 3 : 2 then A, B are
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a
(4, 7),(1, –2)
b
(1, 2),(–4, 7)
c
(7, 4),(2, 1)
d
(2, 1),(7, –4)
answer is B.
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Detailed Solution
R(−1,4),S(11,−8)R,S divides AB¯harmonically in the ratio 3 : 2⇒ AB divides RS¯in the ratio m−n : m+n=3−2 : 3+2=1 : 5A=S−5R1−5=(11,−8)−(−5,20)−4=(−4,7)B=S+5R1+5=(11,−8)+(−5,20)6=(1,2)