The radical axis of the circles x2+y2+2gx+2fy+c=0 and 2x2+y2+3x+2y+2c=0touches the circle x2+y2+2x+2y+1=0, if
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a
g=43and f=2
b
g=43and f=12
c
g=−34and f=2
d
g=34 and f=12
answer is B.
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Detailed Solution
The equation of radical axis is 2g−32x+(2f−1)y=0 (i)It touches the circle x2+y2+2x+2y+1=0∴−2g−32−(2f−1)2g−322+(2f−1)2=1⇒2g+2f−522=2g−322+(2f−1)2 Clearly , g=43 and f=12