The radius of circle passing through (4,9) and the equations of two normals for the circle are x−y+1=0 and 2x+y-7=0 is
210
410
10
310
Given normal lines x−y+1=0&2x+y−7=0
Pt. of intersection = C=(2,3)
Pt P = (4,9)
Radius = CP=r=4+36
=40=210