Q.

The radius of circle passing through (4,9) and the equations of two normals for the circle are x−y+1=0  and 2x+y-7=0 is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

210

b

410

c

10

d

310

answer is A.

(Unlock A.I Detailed Solution for FREE)

Detailed Solution

Given normal lines x−y+1=0&2x+y−7=0 Pt. of intersection = C=(2,3) Pt  P = (4,9) Radius = CP=r=4+36 =40=210
Watch 3-min video & get full concept clarity
Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Online Course for IIT JEE
Best Online Course for NEET
Best Online Course for CBSE
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Online Course for IIT JEE
Best Online Course for NEET
Best Online Course for CBSE
whats app icon