The radius of circle passing through (4,9) and the equations of two normals for the circle are x−y+1=0 and 2x+y-7=0 is

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210

410

310

answer is A.

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Detailed Solution

Given normal lines x−y+1=0&2x+y−7=0 Pt. of intersection = C=(2,3) Pt P = (4,9) Radius = CP=r=4+36 =40=210

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