The radius of the circle touching the straight lines x−2y−1=0 and 3x−6y+7=0 is
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a
12
b
53
c
3
d
5
answer is B.
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Detailed Solution
Given lines are parallel to each other ∴ distance between the parallel lines = diameter of the circle∴ radius =distance between the parallel lines2 =12.|73+1|(1+4)=53