Q.

The radius of the circle touching the straight lines x−2y−1=0  and 3x−6y+7=0  is

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a

12

b

53

c

3

d

5

answer is B.

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Detailed Solution

Given lines are parallel to each other ∴  distance between the parallel lines = diameter of the circle∴  radius =distance between the parallel lines2 =12.|73+1|(1+4)=53
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The radius of the circle touching the straight lines x−2y−1=0  and 3x−6y+7=0  is