Q.
The radius of a circular plate is increasing at the rate of 0.02 cm/sec. when the radius is 10cm. Then the rate at which the area increases is
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a
0.4π sq.cm/sec
b
0 .5π sq.cm/sec .
c
0.6π sq.cm/sec
d
0.1π sqcm/sec
answer is A.
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Detailed Solution
drdt=0.02, r=10 A=πr2 dAdt=2πr.drdt=2π(10)(0.02)=2π(0.2) = 0.4π
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