The radius of the largest circle lying in the first quadrant and touching 4x+3y=12 and co-ordinate axes is
5
6
7
8
Given line is 4x+3y=12 ….(1)
Since the radius of the largest circle lying in the first quadrant then centre is C(r,r) .
Since the circle touches the line then
r=d =The perpendicular distance from centre to the line.
⇒r=|4r+3r−12|16+9
⇒5r=|7r−12|
⇒7r−12=±5r
⇒r=1,6 .