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Q.

A random variable X has poisson distribution with mean 2. Then P(x ≥  2) =

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a

1−3e2

b

3e2

c

2e2

d

0

answer is A.

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Detailed Solution

λ=2,  P(X≥2)=1−P(X=0)−P(X=1)=1−e−2[200!+211!]                       =  1−e−2.(3)
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