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a
π3,π2∪π2,2π3
b
0,π2
c
2π3,π
d
none of these
answer is A.
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Detailed Solution
fx=sec-1log3tanx+logtanx3. =sec-1log3tanx+1log3tanxNow, for log3tanx to get defined, tanx∈0,∞or log3tanx∈-∞,∞ or log3tanx∈RAlso, x+1x≤-2 or x+1x≥2i.e., log3tanx+1log3tanx≤-2or log3tanx+1log3tanx≥2i.e., sec-1log3tanx+1log3tanx≤sec-1-2or sec-1log3tanx+1log3tanx≥sec-12i.e., fx≤2π3 or fx≥π3i.e.,fx∈π3,π2∪π2,2π3