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Questions  

The range of f(x)=sgnx22x+3 is

a
1
b
1
c
{0}
d

detailed solution

Correct option is A

x2−2x+3=(x−1)2+2>0∀x∈R or f(x)=sgn⁡x2−2x+3=1 Hence, the range is {1} .

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