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Q.

The range of f(x)=sgn⁡x2−2x+3 is

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a

1

b

1

c

{0}

d

answer is A.

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Detailed Solution

x2−2x+3=(x−1)2+2>0∀x∈R or f(x)=sgn⁡x2−2x+3=1 Hence, the range is {1} .
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