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Questions  

The range of f(x)=sin2xsinx+1 is

a
34,3
b
34,3
c
34,3
d
34,3

detailed solution

Correct option is A

f(x)=sin2⁡x−sin⁡x+1=sin⁡x−122+34 Now, −1≤sin⁡x≤1 or −32≤sin⁡x−12≤12 or 0≤sin⁡x−122≤94 or 34≤sin⁡x−122+34≤3 Hence, the range is 34,3 .

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