Q.
The range of f(x)=sin2x−sinx+1 is
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a
34,3
b
34,3
c
34,3
d
34,3
answer is A.
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Detailed Solution
f(x)=sin2x−sinx+1=sinx−122+34 Now, −1≤sinx≤1 or −32≤sinx−12≤12 or 0≤sinx−122≤94 or 34≤sinx−122+34≤3 Hence, the range is 34,3 .
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