Q.

Range of the function fx=cosKsinx is  [-1,1], then the least positive integral value of K will be

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a

1

b

2

c

3

d

4

answer is D.

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Detailed Solution

y=cosKsinx          cos-1yK=sinx     ⇒  -1≤cos-1yK≤1    ⇒   -K≤cos-1y≤K    Now    cos-1y∈0,π       ⇒K=4
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