Range of the function f(x)=cos−1log4x−π2+sin−11+x24x is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
0,π2+π2
b
π2,π2+π2
c
π6,π2
d
π6
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
fx=-sin-1logx 4 +sin-11+x24x since sin-1x + cos-1x=π2 domain of first function is 1 only since -sin-1 logx 4 ≥0 ⇒ sin-1logx 4 ≤ 0 ⇒ logx 4 ≤sin0 ⇒ logx 4 =0 ⇒ x=1 therefore fx domain also 1 since Domain of f+g=Domain of f∩Domain of g Range of fx = f1 =-sin-1 0 +sin-11+14 =sin-112 =π6