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 The range of the function, f(x)=cot1log0.5x42x2+3 is

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a
(0,π)
b
(0,3π/4]
c
[3π/4,π)
d
[π/2,3π/4]

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detailed solution

Correct option is C

x4-2 x2+3 = x2-12+2 ≥2 ⇒logx4-2x2+3 0.5  ≤ log 2 0.5  =-log 2 2 =-1   since x≥y ⇒logx a  ≤ logy a  if 0


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