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Q.

The range of the function f(x)=ex−e|x|ex+e|x| is

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a

(−∞,∞)

b

[0,1)

c

(−1,0]

d

(−1,1)

answer is C.

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Detailed Solution

f(x)=ex−e|x|ex+e|x|=0,    x≥0ex−e−xex+e−x,    x<0 Clearly, f(x) is identically zero if x≥0----(1)∵    x<0    e2x<1 or 00 and 1+y1−y<1 or (y+1)(y−1)<0 and 2y1−y<0 i.e.,  −11 or −1
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The range of the function f(x)=ex−e|x|ex+e|x| is