First slide
Functions (XII)
Question

 The range of the function f(x)=exe|x|ex+e|x| is 

Moderate
Solution

f(x)=exe|x|ex+e|x|=0,    x0exexex+ex,    x<0

 Clearly, f(x) is identically zero if x0----(1)

    x<0    e2x<1 or 0<e2x<1    0<1+y1y<1

 or 1+y1y>0 and 1+y1y<1 or (y+1)(y1)<0 and 2y1y<0

 i.e.,  1<y<1 and y<0 or y>1

 or 1<y<0------(2)

 Combining (1) and (2), we get 1<y0 or Range =(1,0] . 

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App