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Questions  

 The range of the function f(x)=exe|x|ex+e|x| is 

a
(−∞,∞)
b
[0,1)
c
(−1,0]
d
(−1,1)

detailed solution

Correct option is C

f(x)=ex−e|x|ex+e|x|=0,    x≥0ex−e−xex+e−x,    x<0 Clearly, f(x) is identically zero if x≥0----(1)∵    x<0    e2x<1 or 00 and 1+y1−y<1 or (y+1)(y−1)<0 and 2y1−y<0 i.e.,  −11 or −1

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