The range of the function f (x) = loge (3x2 – 4x + 5) is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
−∞,loge113
b
loge113,∞
c
−loge113,loge113
d
None of these
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
f (x) is defined if 3x2 – 4x + 5 > 0⇒3x2−43x+53>0⇒3x−232+119>0which is true for all real x.∴ Domain ( f ) = (– ∞, ∞)y=loge3x2−4x+5⇒ey=3x2−4x+5 ⇒3x2−4x+5−ey=0For x to be real,16−125−ey≥0⇒12ey≥44⇒ey≥113 ⇒y≥loge113∴ Range of f=loge113,∞