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Questions  

 The range of the function f(x)=tanπ29x2 is 

a
[0,3]
b
(0,3)
c
[0,3)
d
0,13

detailed solution

Correct option is A

For f(x) to be defined ,π29−x2≥0⇒−π3≤x≤π3 Domain of f=−π3,π3The greatest value off(x)=tan⁡π29−0=3  when x=0 and the least value of f(x)=tan⁡π29−π29=0 when x=π3  Range of function =[0,3]

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