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Questions  

 The range of the function f(x)=tanπ29x2 is 

a
[0,3]
b
(0,3)
c
[0,3)
d
0,13

detailed solution

Correct option is A

f(x)=tanπ29−x2 ⇒π29−x2≥0⇒x2-π29≤0 ⇒x∈-π 3,π 3 range of is 0, 3

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