Q.

The range of the function f(x)=tanπ29−x2 is

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a

[0,3]

b

(0,3)

c

[0,3)

d

0,13

answer is A.

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Detailed Solution

f(x)=tanπ29−x2 ⇒π29−x2≥0⇒x2-π29≤0 ⇒x∈-π 3,π 3 range of is 0, 3
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