The range of the function fx= 7-xPx-3 is
{1,2,3}
{1,2,3,4,5,6}
{1, 2, 3, 4}
{1, 2, 3, 4, 5}
We have fx= 7-xPx-3=7-x!10-2x!
We must have 7-x>0, x≥3, and 7-x≥x-3. Therefore,
x<7,x≥3, and x≤5or 3≤x≤5or x=3,4,5
Now, f3=4!4!=1, f4=3!2!=3, f5=2!0!=2.Hence, Rf=1,2,3.