Download the app

Questions  

 The range of the function f(x)=|x1|+|x2| , 1x3, is 

a
[1,3]
b
[1,5]
c
[3,5]
d
none of these

detailed solution

Correct option is B

Clearly, from the graph, the range is [1,f(−1)]≡[1,5] .  If x<1,f(x)=−(x−1)−(x−2)=−2x+3 In this interval, f(x) is decreasing.  If 1≤x<2,f(x)=x−1−(x−2)=1 In this interval, f(x) is constant.  If 2≤x≤3,f(x)=x−1+x−2=2x−3 .  In this interval, f(x) is increasing. ∴maxf(x)= the greatest among f(−1) and f(3)=5minf(x)=f(1)=1 So, range =[1,5]

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

Find the  range of f(x) f(x)=sin1[x] 


phone icon
whats app icon