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Questions  

The range of the function f(x)=1x2x2+3 is

a
-1,13
b
-1,13
c
−1,13
d
−1,13

detailed solution

Correct option is A

f(x)=y=1−x2x2+3⇒ yx2+3y=1−x2⇒ x2=1−3yy+1 Now x2≥0⇒1−3yy+1≥0⇒3y−1y+1≤0⇒3y-1y+1≤0⇒y+1y-13≤0 Hence, y∈(−1,1/3]

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