The range of the function y=sin−1x21+x2 is
0,π2
None of these
Clearly, for y to be defined, x21+x2≤1 which is true for all x ∈ R. So, the domain = (– ∞, ∞). Now, y=sin−1x21+x2⇒x21+x2=siny ⇒x=x21+x2For x to be real, sin y ≥ 0 and 1 – sin y > 0⇒0≤siny<1⇒y∈0,π2∴ Range =0,π2