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Questions  

The Range of  tan12x1+x2is

a
−π4,π4
b
−π2,π2
c
(−π2,π4]
d
π4,π2

detailed solution

Correct option is A

We have 1+x2≥2|x|⇒2|x|1+x2≤1⇒−1≤2x1+x2≤1 ⇒tan-1-1≤tan-12x1+x2≤tan-11  ∵tan-1 is increasing ⇒-π4≤tan-12x1+x2≤π4

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