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Questions  

The range of tan12x1+x2  is

a
-π4,π4
b
-π,π
c
−π4,π4
d
−π2,3π4

detailed solution

Correct option is A

First, we must get the range of2x1+x2=y We have yx2−2x+y=0 Since x is real, D≥0 , i.e., 4−4y2≥0 or −1≤y≤1 . So, tan−1⁡(y)∈−π4,π4 (As tan⁡x is an increasing function)

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