The range of the value of p for which the equation sincos−1(cos(tan−1x))=phas a solution is
(−12,12]
[0,1)
[12,1)
(-1,1)
sincos−1(cos(tan−1x))=p
For x∈R,tan−1x∈(−π/2,π/2)
⇒cos(tan−1x)∈(0,1]
⇒cos−1cos(tan−1x)∈[0,π/2)
⇒sin[cos−1(cos(tan−1x))]∈[0,1) ⇒p∈[0,1)