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Questions  

The range of the value of p for which the equation sincos1(cos(tan1x))=phas a solution is

a
(−12,12]
b
[0,1)
c
[12,1)
d
(-1,1)

detailed solution

Correct option is B

sincos−1(cos(tan−1x))=pFor x∈R,tan−1x∈(−π/2,π/2)⇒cos(tan−1x)∈(0,1]⇒cos−1cos(tan−1x)∈[0,π/2)⇒sin[cos−1(cos(tan−1x))]∈[0,1) ⇒p∈[0,1)

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