First slide
Introduction to real valued functions
Question

The range of |x2|+|x5|  is

Moderate
Solution

f(x)=|x2|+|x5|  and domain f = R

For x<2,f(x)=2x+5x=72x>3;

For 2<x<5f(x)=x2+5x=3

For x>5,f(x)=x2+x5=2x7>3

Range  f=[3,)

0R   Range of x-a+x-b is [b-a,) =[5-2,)=[3,)

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