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The range of the $y = \sqrt{9 - x^{2}}$ is

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9,∞

(9,∞)

0,3

(3,∞)

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detailed solution

Correct option is C

9−x2 Least value of square root is 0 when 9−x2=0 or x=±3 Also, greatest value of 9−x2 is 9 when x=0 . Hence we have 0≤9−x2≤9⇒9−x2∈[0,3]

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The range of the y=9−x2 is

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The range of the $y = \sqrt{9 - x^{2}}$ is