The rate of growth of bacteria in a culture is proportional to the number of bacteria present, and the bacteria count is 1000 at initial time at t=0. The number of bacteria is increased by 20% in 2 hours. If population of bacteria is 2000 after kloge65hours, then kloge22is equal to
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a
2
b
8
c
16
d
4
answer is D.
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Detailed Solution
Let x be the number of bacteria present at time t, it givesdxdt=kx Integrate both sides ⇒lnx=kt+c, The initial condition is0,1000 Hencec=ln1000 At t = 2,x=1000+1000×20100=1200 Log 1200=2k1+log1000⇒2k1=log12001000=log65⇒k1=12log65 ∴logx=12log65t+log1000 Given log2000=12log65.k+log1000log65 ⇒k=2log2 kloge22=22=4