Ratio of middle terms in (px3+qx2)15 is

Given expansion (px3+qx2)15 is Index of the expansion n=15  then middle terms are 15+12=8,15+32=98th  term: Tr+1= nCr xn−r (a)r T8=T7+1=15c7(px3)8(qx2)7T8=T7+1=15c7(p)8(x3)8(q)7(x−2)79th  term: Tr+1= nCr xn−r (a)r T9=T8+1=15c8(px3)7(qx2)8T9=T8+1=15c8(p)7(x3)7(q)8(x−2)8  Ratio of middle terms in(px3+qx2)15 isT8T9=T7+1T8+1=15c7(p)8(x3)8(q)7(x−2)715c8(p)7(x3)7(q)8(x−2)8                      =px3qx2=px5:q