The ratio of the roots of the equation ax2+bx+c=0 is same as the ratio of the roots of the equation px2+qx+r=0. If D1 and D2 are the discriminants of ax2+bx+c=0 and px2+qx+r=0 respectively, then D1:D2=
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a
a2p2
b
b2q2
c
c2r2
d
none of these
answer is B.
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Detailed Solution
Let α1, β1 be the roots of ax2+bx+c=0 and α2, β2 be the roots of px2+qx+r=0. Then, α1β1=α2β2 [Given]⇒ α1+β1α1−β1=α2+β2α2−β2 [Applying componendo land dividendo]⇒ α1+β12α1−β12=α2+β22α2−β22⇒ α1+β12α1+β12−4α1β1=α2+β22α2+β22−4α2β2⇒ b2/a2b2−4aca2=q2/p2q2−4rpp2⇒b2D1=q2D2⇒D1D2=b2q2
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The ratio of the roots of the equation ax2+bx+c=0 is same as the ratio of the roots of the equation px2+qx+r=0. If D1 and D2 are the discriminants of ax2+bx+c=0 and px2+qx+r=0 respectively, then D1:D2=